![MathType on Twitter: "In #Quantum #Mechanics we can use the #commutator of two operators to know if the observables associated to those #operators are compatible, in which case we can find a MathType on Twitter: "In #Quantum #Mechanics we can use the #commutator of two operators to know if the observables associated to those #operators are compatible, in which case we can find a](https://pbs.twimg.com/media/FPEwHFQXsAMa4hU.jpg:large)
MathType on Twitter: "In #Quantum #Mechanics we can use the #commutator of two operators to know if the observables associated to those #operators are compatible, in which case we can find a
![SOLVED: Question 5: Commutator Identities Prove each of the following commutator identities: (a) [AB,C] A[B,C] + [A,C]B (b) [x",p] = ihnxn-1 (c) [f (x),p] = ihdf dx SOLVED: Question 5: Commutator Identities Prove each of the following commutator identities: (a) [AB,C] A[B,C] + [A,C]B (b) [x",p] = ihnxn-1 (c) [f (x),p] = ihdf dx](https://cdn.numerade.com/ask_images/2e71f495003747b28c5b2a97cd28ca5b.jpg)
SOLVED: Question 5: Commutator Identities Prove each of the following commutator identities: (a) [AB,C] A[B,C] + [A,C]B (b) [x",p] = ihnxn-1 (c) [f (x),p] = ihdf dx
![SOLVED: Commutator algebra 1/ Let A and B be two arbitrary observables. Is their COIInutator Iermitial; unitary; anything else? Justify yOur answer with rigorous derivation 2 / Prove the following relations where SOLVED: Commutator algebra 1/ Let A and B be two arbitrary observables. Is their COIInutator Iermitial; unitary; anything else? Justify yOur answer with rigorous derivation 2 / Prove the following relations where](https://cdn.numerade.com/ask_images/3e8beaa533b145a2850109e567a29cb8.jpg)
SOLVED: Commutator algebra 1/ Let A and B be two arbitrary observables. Is their COIInutator Iermitial; unitary; anything else? Justify yOur answer with rigorous derivation 2 / Prove the following relations where
![calculus - What do these commutator identities have to do with the product rule for derivatives? - Mathematics Stack Exchange calculus - What do these commutator identities have to do with the product rule for derivatives? - Mathematics Stack Exchange](https://i.stack.imgur.com/0Nvsd.jpg)
calculus - What do these commutator identities have to do with the product rule for derivatives? - Mathematics Stack Exchange
![SOLVED: a) Given the results in Question 2 and the commutator rules [AB,€] = A[B,C] + [A,CJB [A,BC] = [A,BJc + B[A,C] Evaluate the commutators [M2,Mx], [M2,My], and [M2,Mz]- Recall M = SOLVED: a) Given the results in Question 2 and the commutator rules [AB,€] = A[B,C] + [A,CJB [A,BC] = [A,BJc + B[A,C] Evaluate the commutators [M2,Mx], [M2,My], and [M2,Mz]- Recall M =](https://cdn.numerade.com/ask_images/cb2e0920dac74e4a925daab01bc1c15e.jpg)